{"id":106,"date":"2024-04-01T05:55:11","date_gmt":"2024-04-01T05:55:11","guid":{"rendered":"http:\/\/dev.lode.com\/?p=106"},"modified":"2024-04-01T05:55:11","modified_gmt":"2024-04-01T05:55:11","slug":"kinh-nghiem-7-cach-bat-lo-hieu-qua","status":"publish","type":"post","link":"https:\/\/kenhcaude.com\/kinh-nghiem-7-cach-bat-lo-hieu-qua\/","title":{"rendered":"Kinh nghi\u1ec7m 7 c\u00e1ch b\u1eaft l\u00f4 hi\u1ec7u qu\u1ea3"},"content":{"rendered":"
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1. C\u00e1ch b\u1eaft l\u00f4 t\u1ed5ng  <\/strong><\/h5>\n

C\u00e1c b\u1ea1n h\u00e3y nh\u00ecn v\u00e0o h\u00e0ng 3 s\u1ed1 gi\u1eefa c\u1ee7a gi\u1ea3i 5 v\u00e0 6. C\u00e1ch b\u1eaft lo nh\u01b0 sau:
\nGi\u1ea3i 5: G2.4 v\u00e0 G5.4 k\u1ebft h\u1ee3p v\u1edbi Gi\u1ea3i 6: G2.3 v\u00ed d\u1ee5 nh\u01b0 ng\u00e0y 17\/10 ta c\u00f3 t\u1ed5ng 3 s\u1ed1 l\u00e0 7+7+5=19. Ta \u0111\u00e1nh c\u1eb7p 191 khung 3 ng\u00e0y.
\nC\u00e1ch n\u00e0y \u00e1p d\u1ee5ng cho khung 3 ng\u00e0y. R\u1ea5t \u00edt khi v\u01b0\u1ee3t max. C\u00e1c b\u1ea1n c\u00f3 th\u1ec3 xem l\u1ea1i k\u1ebft qu\u1ea3 tr\u01b0\u1edbc \u0111\u00e2y \u0111\u1ec3 ki\u1ec3m nghi\u1ec7m. B\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u1ed9ng th\u00eam m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p b\u1ed5 tr\u1ee3 m\u00e0 m\u00ecnh \u0111\u00e3 ho\u00e0n th\u00e0nh trong khu ch\u0103n nu\u00f4i 21 c\u1eb7p th\u00f4ng li\u00ean t\u1ee5c.<\/p>\n

2. C\u00e1ch b\u1eaft l\u00f4 h\u00ecnh tam<\/h5>\n

C\u00e1c b\u1ea1n v\u1eabn nh\u00ecn v\u00e0o Gi\u1ea3i 5 v\u00e0 6 c\u1ee5 th\u1ec3 nh\u01b0 sau:
\nGi\u1ea3i 5: G6.3 nh\u00ecn l\u00ean Gi\u1ea3i 5 G3.4 nh\u00ecn xu\u1ed1ng gi\u1ea3i 6 G3.3 c\u1ee5 th\u1ec3 nh\u01b0 ng\u00e0y 17\/10 ta c\u00f3 s\u1ed1 1, 9 v\u00e0 5. C\u00e1ch b\u1eaft lo h\u00ecnh tam n\u00e0y th\u01b0\u1eddng \u00e1p d\u1ee5ng cho \u0111\u00e1nh l\u00f4 t\u00f4 b\u1ea1ch th\u1ee7 n\u1ebfu Gi\u1ea3i 5 G3.4 ch\u00f9ng s\u1ed1 v\u1edbi Gi\u1ea3i 6 G3.3 th\u00ec ta l\u1ea5y s\u1ed1 \u1edf gi\u1eefa l\u00e0m t\u00e2m \u0111i\u1ec3m ch\u1ebfch l\u00ean tr\u00ean v\u00e0 xu\u1ed1ng d\u01b0\u1edbi \u0111\u00e1nh khung 5 ng\u00e0y t\u01b0\u01a1ng \u0111\u1ed1i an to\u00e0n, \u0111\u00e1nh l\u1ed9n khung 3 ng\u00e0y c\u0169ng \u0111\u01b0\u1ee3c. C\u00f2n n\u1ebfu kh\u00f4ng tr\u00f9ng nhau ta s\u1ebd l\u1ecdc \u0111\u01b0\u1ee3c 2 s\u1ed1 nh\u01b0 h\u00f4m nay l\u00e0: 19 v\u00e0 15.<\/p>\n

3. C\u00e1ch b\u1eaft l\u00f4 ch\u1ea1m 2 nh\u00e1y<\/h5>\n

C\u00e1ch n\u00e0y kh\u00f4ng c\u1ea7u k\u1ef3. C\u00e1c b\u1ea1n \u0111\u1ec3 \u00fd h\u00f4m qua c\u1eb7p n\u00e0o v\u1ec1 2 nh\u00e1y h\u00f4m nay \u0111\u00e1nh ch\u1eb7n \u0111\u1ea7u \u0111u\u00f4i c\u1ee7a c\u1eb7p s\u1ed1 \u0111\u00f3.
\nV\u00ed d\u1ee5: H\u00f4m qua c\u00f3: 2 nh\u00e1y 46 h\u00f4m nay ng\u00e0y 17\/10 ch\u00fang ta \u0111\u00e1nh 45 v\u00e0 47. C\u00e1ch n\u00e0y r\u1ea5t d\u1ec5 v\u01b0\u1ee3t max nh\u01b0ng c\u0169ng kh\u00e1 hi\u1ec7u qu\u1ea3. N\u00ean d\u00f9ng \u0111\u1ec3 b\u1ed5 tr\u1ee3 cho t\u1ed5ng c\u00e1c c\u00e1ch \u0111\u00e1nh.<\/p>\n

4. C\u00e1ch b\u1eaft lo tr\u00f9ng c\u1eb7p<\/h5>\n

C\u00e1c b\u1ea1n nh\u00ecn l\u00ean Gi\u1ea3i 2 G1. N\u1ebfu th\u1ea5y s\u1ed1 ra c\u00f3 d\u1ea1ng ch\u1ecdn \u0111\u1ea7u ch\u1ecdn \u0111\u00edt. V\u00ed d\u1ee5 ng\u00e0y h\u00f4m kia c\u00f3 26404 t\u1ee9c l\u00e0 d\u1ea1ng s\u1ed1 chia ra c\u00f3 c\u1eb7p 040, ta kh\u00f4ng b\u1eaft lo 040 nh\u00e9 m\u00e0 thay v\u00e0o \u0111\u00f3 ta ch\u1ecdn \u0111\u01b0\u1ee3c c\u1eb7p 262 cho khung 3 ng\u00e0y. C\u00e1ch n\u00e0y ch\u1ec9 \u00e1p d\u1ee5ng khi c\u00e1c s\u1ed1 c\u1ee7a G1 c\u00f3 d\u1ea1ng \u0111\u1ea7u \u0111\u00edt ta b\u1ecf \u0111\u1ea7u \u0111\u00edt \u0111\u00e1nh c\u1eb7p \u201ckh\u00f4ng ra \u0111\u00e2u v\u00e0o \u0111\u00e2u\u201d.
\nTr\u01b0\u1eddng h\u1ee3p khoai c\u00f3 d\u1ea1ng v\u00ed d\u1ee5 s\u1ed1 48888 ho\u1eb7c 88848 nh\u01b0 th\u1ebf n\u00e0y ta \u0111\u00e1nh 04, 40. Tr\u01b0\u1eddng h\u1ee3p s\u1ed1 c\u00f3 d\u1ea1ng 33848 ho\u1eb7c 84338 ta \u0111\u00e1nh 32 v\u00e0 34. B\u1eb1ng c\u00e1ch n\u00e0y ta s\u1ebd r\u1ea5t d\u1ec5 \u0103n k\u1ebft qu\u1ea3 2 nh\u00e1y tr\u00ean 1 c\u1eb7p \u0111\u00f4i.<\/p>\n

5. C\u00e1ch b\u1eaft l\u00f4 \u0111\u01b0\u1eddng th\u1eb3ng<\/h5>\n

C\u00e1c b\u1ea1n nh\u00ecn l\u00ean Gi\u1ea3i 3 G2.3 + Gi\u1ea3i 3 G4.3 + Gi\u1ea3i 6 G2.2 nh\u01b0 ng\u00e0y h\u00f4m nay ta c\u00f3 t\u1ed5ng c\u1ee7a 3 s\u1ed1: 4+3+3=10.
\nNh\u01b0 v\u1eady l\u00e0 c\u00e1c b\u1ea1n \u0111\u00e3 ch\u1ecdn \u0111\u01b0\u1ee3c c\u1eb7p 101.<\/p>\n

6. C\u00e1ch b\u1eaft l\u00f4 h\u00ecnh tam gi\u00e1c \u0111\u1ec1u<\/h5>\n

C\u00e1c b\u1ea1n nh\u00ecn v\u00e0o s\u1ed1 gi\u1eefa c\u1ee7a Gi\u1ea3i 1 k\u1ebft h\u1ee3p v\u1edbi gi\u1ea3i 3 G4.1 v\u1edbi G6.5 nh\u01b0 ng\u00e0y h\u00f4m nay ta c\u00f3 3 s\u1ed1 8, 7, 7. L\u1ea5y s\u1ed1 8 l\u00e0m t\u00e2m ta c\u00f3 c\u1eb7p 787. C\u1eb7p n\u00e0y h\u00f4m nay theo nh\u1eadn \u0111\u1ecbnh ch\u00f9ng nhau s\u1ed1 7 r\u1ea5t d\u1ec5 ra ng\u00e0y 1 ho\u1eb7c c\u00f3 th\u1ec3 ch\u1ecdn \u0111\u00e1nh b\u1ea1ch th\u1ee7 87 \u00e1p d\u1ee5ng cho khung 5 ng\u00e0y.<\/p>\n

7. C\u00e1ch b\u1eaft l\u00f4 d\u1ea1ng t\u1ee9 qu\u00fd \u2013 ng\u0169 qu\u00fd<\/h5>\n

C\u00e1ch b\u1eaft lo d\u00e0nh cho c\u1eb7p s\u1ed1 c\u00f3 d\u1ea1ng 4 s\u1ed1 ch\u00f9ng nhau c\u1ee7a 1 gi\u1ea3i trong 27 gi\u1ea3i.
\nTr\u00ean \u0111\u00f3 l\u00e0 7 c\u00e1ch l\u00f4 hi\u1ec7u qu\u1ea3
\nCh\u00fac c\u00e1c b\u1ea1n may m\u1eafn.<\/p>\n